A block of ice of mass 40g at 0^oC is placed in a calorimeter containing 400g of water at 20^oC. Ignoring heat absorbed by the...

      

A block of ice of mass 40g at 0^oC is placed in a calorimeter containing 400g of water at 20^oC. Ignoring heat
absorbed by the calorimeter, determine the final temperature of the mixture after all the ice has melted.
Take s.h.c.of water= 4200JKg-1K-1 and the s.l.h. of fusion of ice= 340, 000JKg-1.

  

Answers


Moraa
Heat lost by the hot water= heat gained by melting ice + heat gained by melted ice
mc??h= mlf + mc??m
0.4*4200*(20-?) = (0.04*340, 000) + (0.04*4200*?)
33600-380? = 13600 + 38?
1848?=20000
T=20000/1848 =5.82^oC
Moraa orina answered the question on April 10, 2018 at 17:59


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